x^2-7x-540=0

Solution for x^2-7x-540=0 equation:

Simplifying
x2 + -7x + -540 = 0

Reorder the terms:
-540 + -7x + x2 = 0

Solving
-540 + -7x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-20 + -1x)(27 + -1x) = 0

Subproblem 1
Set the factor '(-20 + -1x)' equal to zero and attempt to solve:

Simplifying
-20 + -1x = 0

Solving
-20 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + -1x = 0 + 20

Combine like terms: -20 + 20 = 0
0 + -1x = 0 + 20
-1x = 0 + 20

Combine like terms: 0 + 20 = 20
-1x = 20

Divide each side by '-1'.
x = -20

Simplifying
x = -20
Subproblem 2
Set the factor '(27 + -1x)' equal to zero and attempt to solve:

Simplifying
27 + -1x = 0

Solving
27 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + -1x = 0 + -27

Combine like terms: 27 + -27 = 0
0 + -1x = 0 + -27
-1x = 0 + -27

Combine like terms: 0 + -27 = -27
-1x = -27

Divide each side by '-1'.
x = 27

Simplifying
x = 27
Solution
x = {-20, 27}